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Like every day in 11ª Pre-Calculus class, we start off by the P.O.D (problem of the day). Today’s P.O.D was on a topic we already learned but which was helpful as a review for our upcoming final exam.\
P.O.D 6/7
Solve the equation for all θ є [0,360º] 3sec q-9 = 1.
First to solve, we have to isolate θ, so we subtract 9 from both sides, and then we divide each side by 3 and finally get the inverse of sec on both sides.
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Now we have to find all 1st revolution angles, we know that the angles are located in the first and fourth quadrant because it a positive angle. So we ºsubtract 72.54º from 360º.
360º-72.54º ≈ 287.46º so,
q ≈ 72.54º, 287.46º
REMEMBER TO STUDY QUIZ TOMORROW!!
TOPICS:
-SIGMA NOTATION
-INFINITE SERIES
-LIMITS
11A’S FINAL PLAN:
-Mr. Alcantara will post a final exam study list to the block for those of you interested.
-The post will have an assignment on the back for those students who will not have time to do a second block.
Yesterday we ended off in a sigma notation problem, today we picked up were we left yesterday and solved it.
Express the series in Sigma notation and then use
Sigma properties to find the sum:
3•2+3•3+3•4+3•5 …+3•18
To solve the problem we first have to identify what type of series is. We can tell is an arithmetic series because 3 is always being multiplied by a number that increases by 1.
Now we have to find the number of terms we have to add. So,
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Last Property of Sum:
n
Σ c where c is a constant ( not dependent on n)
n=1
ex:
n
Σ 4 = 4+4+4+4+4 = 5•4= 20
n=1 ( add 4, 5 times )
PROBLEMS:
16
• Find Σ 3k-10
n=1
First evaluate the problem, what is it saying? Their sayings add 3k-10, 16 times. To make it easier we have the properties of sum to solve this problem. Divide the proble in two parts and solve for each.
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PRACTICE PROBLEMS AND SOLUTIONS:
1. Find the sum using sigma notation 1•3+3•5+5•7 +... 99•101
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2. ∞ n-1
Σ 7• 2/3
k=1
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Lucho and Mr. Janke run a race. Lucho runs 1.5 times as fast as Mr. Janke. If Mr. Janke has an 8m head start, how fast will Mr. Janke run before Lucho catches him?
* Lucho speed is 3/2 Mr. Janke's->
* Lucho covers 3/2 the distance that Mr. Janke covers in the same time->
* Mr. Janke covers 2/3 the distance that Lucho covers in the same time->
* By the time Lucho makes up the 8m, Mr. Janke will have gone 2/3(8m)->
* The lead that Lucho has to make up will be 2/3 less each time.
Lucho runs:
Mr. Janke runs 24-8=16m
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4. Find and Justify lim sn , where tn 10(3/2)
n->∞
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5. Find the sum: 2•4+6•8+10•12+...+398•400
1 2 3 ?
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6. Express the series in sigma notation and then use sigma properties to find the sum:
200+192+184+...-64
Arithmetic or Geometric?
d=-8
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NO HOMEWORK ! BUT STUDY HARD FOR FINAL EXAMS AND EXAM TOMORROW !....
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1 comment:
Sofy and Cristy,
something similar happened to me the first time i tried posting my scribe. You should try viewing your scribe in HTML format and then publish it. That will fix your problem.
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