Tuesday, May 1, 2007

Sequences Quiz

1. I think this is not a very straight forward topic and it is not crazy to say that many people won't do very well, I hope I'm not one of them. What I mean with this, is that there are several ways of writting down or getting to the final solution or term of a sequence. As I was doing some problems of the book, I came up with answers that worked, because I prooved them first, but the book showed a completely different answer that I couldn't imagine how to get to. I know how to answer a problem, I just need more security in what I'm doing. I question I have would be: how to write an explicit equation for a sequence that is neither arithmetic or geometric?

2. The mistakes I'm most likely going to make would be identifying correctly the definition of the sequences. In arithmetic sequences it is very easy, I mean more in geometric sequences or exponential sequences. I hope that I would be focused enough tomorrow to do it correctly.

3. An example of a question is the following:

Given that T(1)=9 and T(3)=24 of an Arithmetic Sequence.
A) Find first 5 terms of the sequence.
B) Write a recursive definition for the sequence.
C) Write an explicit definition for the sequence.
D) Find the 56th term of the sequence.

3 comments:

MAC said...

These are the answers to the problem:

A) T1:9
T2:16.5
T3:24
T4:31.5
T5:39

B)Tn = T(n-1) + 7.5

C)Tn = 9 + 7.5 (n-1)

D)421.5

Rumidog said...

MAC,

I know this sems obvious to you, but I bet people are asking themselves how you got those 1st five terms. Would you please show them?

MAC said...

How did I get those first five terms?

In the problem I specified that it is an arithmetic sequence, therefore it is the same addition in each jump. If the difference between term 1 and 3 is 15 (24-9=15), and term 2 is exactly in the middle of 9 and 24, we can divide 15 in 2 and we get 7.5 which is the size of each jump.

Term two is the value of term 1 plus 7.5, so 9 + 7.5=16.5.
Term four would be the value of term 3 plus 7.5, so 24 + 7.5=31.5.
And so forth.